Thanks, Timothy. I will try those values. I also appreciate that you
explained the math behind your conclusions.

Can you suggest the best way to cut the PCB tracks (I've done this
before, but never on purpose.) Is an exacto knife a good idea

--- In Doepfer_a100@yahoogroups.com , "Tim Stinchcombe"
<timothy@t...> wrote:

> > While we're at it, connecting +5v. to the CV2 switched input

would

> > make the CV2 knob a wide range tuning knob whenever it is not

being

> > used as a CV attenuator. Zeroing the CV2 knob and centering the
> > fine tuning control would give the nominal pitch. I think I'll

try

> > this on mine. Does anybody have any ideas of what would be the
> > optimal resistor values to use to get a reliable 5v. from the

12v.

> > supply without loading it too much
>
> If you're just thinking of adding a resistor in series with the

50k

> pot, then it will need to be 70kohm, so 12*50/(50+70)=5V with the

pot

> at max. Using a 68k resistor will give just a little more than 5V,
> and its not too expensive current wise, at just 0.1mA (=12/
> (50k+70k)). If you want to arrange it so that it is switched out

when

> a patch cord is inserted, the hardest part will be cutting the

track

> in two places underneath the socket, which obviously requires
> removing it (it would be easiest to cut the old one out, desolder

the

> remains of the pins, cut tracks, add resistor plus one wire,

solder

> in new socket). There are several convenient places to hook-up to

the

> 12V rail.
>
> Tim