no, you patched correctly. I was speaking about the theoretical output
results when inputing sines.

On 10/10/09, Shrewsbury Marie <propane23@...> wrote:
> Hang on, so the X input of Ring mod 2 is the output And the output of Ring
> mod 1 is patched to the normal output of Ring mod 2, like Ring mod 2 is
> patched in reverse
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>
> --- On Sat, 10/10/09, achtung_999 <heinrich.himmelwasser@...> wrote:
>
> From: achtung_999 <heinrich.himmelwasser@...>
> Subject: Re: 1 Mod-demod - Not quite getting this one
> To: Doepfer_a100@yahoogroups.com
> Date: Saturday, October 10, 2009, 3:37 PM
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> Fast answer without listening to the sound yet..In theory
> you should have
>
> the upper sum harmonic with the X input as output from the Mod Demod..
>
> So if your sound is a low sine chances are that the difference harmonic is
>
> too low to hear..
>
> Leaving thereby only the sum harmonic and the leakage from the X input...
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> On Sat, Oct 10, 2009 at 4:23 PM, propane23 <propane23@yahoo. com> wrote:
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>>
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>> Let me see if i've got this right:
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>>
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>> Osc A to Ring mod 1 X input
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>> Osc B to Ring mod 1 Y input
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>> Ring mod 1 output to Ring mod 2 X input
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>> Osc B inverted to Ring mod 2 Y input
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>>
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>> I've had a few goes and i can't tell any difference between 'mod demod'
>> and
>
>> just plain two ring mods in series, the following audio has a VCS in the
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>> patch to switch the Ring mod 2 Y input between inverted and non-inverted
>> on
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>> each new note on.
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>>
>
>> http://homepage. ntlworld. com/marieshrewsb ury/ModDemod% 20101009. wav
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>> It sounds just the same First part is using an LFO in the audio range,
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>> then i swap patch cables to use a VCO instead, but there is no change on
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>> alternate notes.
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