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Subject: RE: [chromapolaris] polaris MOD lever-- what does it really do? [in modern terms...]

From: "Paul D. DeRocco" <pderocco@...>
Date: 2011-04-12

> From: steven
>
> I am wondering about what the mod lever on the polaris
> actually does. it seems to engage the sweep (lfo) at the
> rate that the sweep lever is set. but is its 'detination'
> [to use a modern term] the filter cutoff---or filter
> envelope? or what?? so then, it adds the sweep rate to the
> filter--- at the 'level' set by the assignable control--- and
> how does this differ from the 'vibrato' that also seems to be
> adding this LFO at this single set rate?

In arithmetic terms:

pitch1 = key + transpose + lever2 ∗ bend_lever_range
+ sweep ∗ (osc1_vibrato ∗ delay_envelope + lever1 ∗ mod_lever_range)

pitch2 = key + transpose + lever2 ∗ bend_lever_range
+ sweep ∗ (osc2_vibrato ∗ delay_envelope + lever1 ∗ mod_lever_range)

So you can see that it applies vibrato to both oscillators equally, and has
nothing to do with the filter.

> I have other more
> modern synths that allow you to assign the mod wheel to many
> parameters--so im wondering what does this control do on the
> polaris in 'modern' terms . I kinda wish it did more--or
> could be modded to have more or more intense actions. it
> seems to have a fairly limited scope compared to my other
> synths. any comments/ explainations?

There's also a less modern synth that lets you do this: the Chroma.

--

Ciao, Paul D. DeRocco
Paul mailto:pderocco@...